5y^2-28y+40=0

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Solution for 5y^2-28y+40=0 equation:


Simplifying
5y2 + -28y + 40 = 0

Reorder the terms:
40 + -28y + 5y2 = 0

Solving
40 + -28y + 5y2 = 0

Solving for variable 'y'.

Begin completing the square.  Divide all terms by
5 the coefficient of the squared term: 

Divide each side by '5'.
8 + -5.6y + y2 = 0

Move the constant term to the right:

Add '-8' to each side of the equation.
8 + -5.6y + -8 + y2 = 0 + -8

Reorder the terms:
8 + -8 + -5.6y + y2 = 0 + -8

Combine like terms: 8 + -8 = 0
0 + -5.6y + y2 = 0 + -8
-5.6y + y2 = 0 + -8

Combine like terms: 0 + -8 = -8
-5.6y + y2 = -8

The y term is -5.6y.  Take half its coefficient (-2.8).
Square it (7.84) and add it to both sides.

Add '7.84' to each side of the equation.
-5.6y + 7.84 + y2 = -8 + 7.84

Reorder the terms:
7.84 + -5.6y + y2 = -8 + 7.84

Combine like terms: -8 + 7.84 = -0.16
7.84 + -5.6y + y2 = -0.16

Factor a perfect square on the left side:
(y + -2.8)(y + -2.8) = -0.16

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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